There will be a force of gravity pulling it down as well as a force of tension pulling it up.

There are going to be forces acting on it here. To find the force of tension on the ball, we need to consider our knowledge of centripetal force and act on the ball at point B. If they take the square root of both sides and then divide them by two, it will give us VB equal to the square root of the other side. All we have to do is cross the M because there is a factor on both sides. The velocity at B is something we're interested in finding. Since the ball is a little L higher than it is at point B and that is converted at Point B into kinetic energy, which is given by 1/2 m, the potential of the bowl relative to point B is mass times gravity times little l. At point A, that allows us to easily show that. The ball is higher in the air at point A than it is at point B, so we'll do this using the same amount of energy.

First things first, find the velocity at B. The first thing we're going to do is find the velocity of the ball at point B, then we're going to use that philosophy and knowledge of circular motion to find the tension in the string. They were asked to show that the force of tension in the rope at point B is the same as the force of tension at point L. We have a ball that is on the end of a string, and there is an object at a distance from the bottom of the string that prevents the ball from going down.

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